Base | Representation |
---|---|
bin | 110111111110110110… |
… | …1000001100101101111 |
3 | 102111022101011222221112 |
4 | 1233331231001211233 |
5 | 3432202430240011 |
6 | 131121211422235 |
7 | 11454114601511 |
oct | 1577555014557 |
9 | 374271158845 |
10 | 120220555631 |
11 | 46a92407900 |
12 | 1b37175497b |
13 | b44baba967 |
14 | 5b66759bb1 |
15 | 31d952058b |
hex | 1bfdb4196f |
120220555631 has 12 divisors (see below), whose sum is σ = 133451617992. Its totient is φ = 108209310000.
The previous prime is 120220555577. The next prime is 120220555633. The reversal of 120220555631 is 136555022021.
It is a de Polignac number, because none of the positive numbers 2k-120220555631 is a prime.
It is a super-3 number, since 3×1202205556313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120220555633) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4906385 + ... + 4930826.
It is an arithmetic number, because the mean of its divisors is an integer number (11120968166).
Almost surely, 2120220555631 is an apocalyptic number.
120220555631 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
120220555631 is a deficient number, since it is larger than the sum of its proper divisors (13231062361).
120220555631 is a wasteful number, since it uses less digits than its factorization.
120220555631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9837334 (or 9837323 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 120220555631 its reverse (136555022021), we get a palindrome (256775577652).
The spelling of 120220555631 in words is "one hundred twenty billion, two hundred twenty million, five hundred fifty-five thousand, six hundred thirty-one".
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