Base | Representation |
---|---|
bin | 1010111011110001110100… |
… | …0000110101110010110111 |
3 | 1120120022010211112122210021 |
4 | 2232330131000311302313 |
5 | 3033432230124033421 |
6 | 41322513202310011 |
7 | 2350365564544021 |
oct | 256743500656267 |
9 | 46508124478707 |
10 | 12022100221111 |
11 | 39155a9183052 |
12 | 1421b69058307 |
13 | 6928aa231bb6 |
14 | 2d7c30bab011 |
15 | 15cac8249341 |
hex | aef1d035cb7 |
12022100221111 has 2 divisors, whose sum is σ = 12022100221112. Its totient is φ = 12022100221110.
The previous prime is 12022100221009. The next prime is 12022100221213. The reversal of 12022100221111 is 11112200122021.
It is a balanced prime because it is at equal distance from previous prime (12022100221009) and next prime (12022100221213).
It is a cyclic number.
It is not a de Polignac number, because 12022100221111 - 213 = 12022100212919 is a prime.
It is a super-4 number, since 4×120221002211114 (a number of 53 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12022100221811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011050110555 + 6011050110556.
It is an arithmetic number, because the mean of its divisors is an integer number (6011050110556).
Almost surely, 212022100221111 is an apocalyptic number.
12022100221111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022100221111 is an equidigital number, since it uses as much as digits as its factorization.
12022100221111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 12022100221111 its reverse (11112200122021), we get a palindrome (23134300343132).
The spelling of 12022100221111 in words is "twelve trillion, twenty-two billion, one hundred million, two hundred twenty-one thousand, one hundred eleven".
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