12022111000019 has 2 divisors, whose sum is σ = 12022111000020. Its totient is φ = 12022111000018.

The previous prime is 12022111000001. The next prime is 12022111000021. The reversal of 12022111000019 is 91000011122021.

It is a strong prime.

It is an emirp because it is prime and its reverse (91000011122021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12022111000019 is a prime.

It is a super-2 number, since 2×12022111000019² (a number of 27 digits) contains 22 as substring.

Together with 12022111000021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12022111020019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011055500009 + 6011055500010.

It is an arithmetic number, because the mean of its divisors is an integer number (6011055500010).

Almost surely, 2^{12022111000019} is an apocalyptic number.

12022111000019 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022111000019 is an equidigital number, since it uses as much as digits as its factorization.

12022111000019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 20.

The spelling of 12022111000019 in words is "twelve trillion, twenty-two billion, one hundred eleven million, nineteen", and thus it is an aban number.