12022133011001 has 4 divisors (see below), whose sum is σ = 12022140824100. Its totient is φ = 12022125197904.

The previous prime is 12022133010989. The next prime is 12022133011043. The reversal of 12022133011001 is 10011033122021.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 7706459154601 + 4315673856400 = 2776051^2 + 2077420^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12022133011001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12022133011061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 746306 + ... + 4959963.

It is an arithmetic number, because the mean of its divisors is an integer number (3005535206025).

Almost surely, 2^{12022133011001} is an apocalyptic number.

It is an amenable number.

12022133011001 is a deficient number, since it is larger than the sum of its proper divisors (7813099).

12022133011001 is an equidigital number, since it uses as much as digits as its factorization.

12022133011001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7813098.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12022133011001 its reverse (10011033122021), we get a palindrome (22033166133022).

The spelling of 12022133011001 in words is "twelve trillion, twenty-two billion, one hundred thirty-three million, eleven thousand, one".