Base | Representation |
---|---|
bin | 1010111011110001111011… |
… | …1101111011101100111111 |
3 | 1120120022020010020200020012 |
4 | 2232330132331323230333 |
5 | 3033432312022411221 |
6 | 41322520333213435 |
7 | 2350366443352061 |
oct | 256743675735477 |
9 | 46508203220205 |
10 | 12022133013311 |
11 | 3915615740343 |
12 | 1421b7803127b |
13 | 6928b3c73a75 |
14 | 2d7c352a5731 |
15 | 15cacb07565b |
hex | aef1ef7bb3f |
12022133013311 has 8 divisors (see below), whose sum is σ = 12446113808064. Its totient is φ = 11605160165760.
The previous prime is 12022133013277. The next prime is 12022133013329. The reversal of 12022133013311 is 11331033122021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12022133013311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12022133013361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1751983310 + ... + 1751990171.
It is an arithmetic number, because the mean of its divisors is an integer number (1555764226008).
Almost surely, 212022133013311 is an apocalyptic number.
12022133013311 is a deficient number, since it is larger than the sum of its proper divisors (423980794753).
12022133013311 is an equidigital number, since it uses as much as digits as its factorization.
12022133013311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3503973601.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12022133013311 its reverse (11331033122021), we get a palindrome (23353166135332).
The spelling of 12022133013311 in words is "twelve trillion, twenty-two billion, one hundred thirty-three million, thirteen thousand, three hundred eleven".
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