1202213404141 has 4 divisors (see below), whose sum is σ = 1202225029792. Its totient is φ = 1202201778492.

The previous prime is 1202213404127. The next prime is 1202213404177. The reversal of 1202213404141 is 1414043122021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1202213404141 - 2¹⁷ = 1202213273069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1202213404541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5656305 + ... + 5864998.

It is an arithmetic number, because the mean of its divisors is an integer number (300556257448).

Almost surely, 2^{1202213404141} is an apocalyptic number.

It is an amenable number.

1202213404141 is a deficient number, since it is larger than the sum of its proper divisors (11625651).

1202213404141 is a wasteful number, since it uses less digits than its factorization.

1202213404141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11625650.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1202213404141 its reverse (1414043122021), we get a palindrome (2616256526162).

The spelling of 1202213404141 in words is "one trillion, two hundred two billion, two hundred thirteen million, four hundred four thousand, one hundred forty-one".