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12022141143 = 34007380381
BaseRepresentation
bin10110011001001001…
…10101000011010111
31011000211210001021210
423030210311003113
5144110132004033
65304540112503
7603630341115
oct131444650327
934024701253
1012022141143
11510a204641
1223b6235733
1311979176ac
14820942ab5
154a5695d63
hex2cc9350d7

12022141143 has 4 divisors (see below), whose sum is σ = 16029521528. Its totient is φ = 8014760760.

The previous prime is 12022141129. The next prime is 12022141199. The reversal of 12022141143 is 34114122021.

12022141143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12022141143 - 213 = 12022132951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12022141543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003690188 + ... + 2003690193.

It is an arithmetic number, because the mean of its divisors is an integer number (4007380382).

Almost surely, 212022141143 is an apocalyptic number.

12022141143 is a deficient number, since it is larger than the sum of its proper divisors (4007380385).

12022141143 is an equidigital number, since it uses as much as digits as its factorization.

12022141143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4007380384.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 12022141143 its reverse (34114122021), we get a palindrome (46136263164).

The spelling of 12022141143 in words is "twelve billion, twenty-two million, one hundred forty-one thousand, one hundred forty-three".

Divisors: 1 3 4007380381 12022141143