Base | Representation |
---|---|
bin | 10110011001001001… |
… | …10101000011010111 |
3 | 1011000211210001021210 |
4 | 23030210311003113 |
5 | 144110132004033 |
6 | 5304540112503 |
7 | 603630341115 |
oct | 131444650327 |
9 | 34024701253 |
10 | 12022141143 |
11 | 510a204641 |
12 | 23b6235733 |
13 | 11979176ac |
14 | 820942ab5 |
15 | 4a5695d63 |
hex | 2cc9350d7 |
12022141143 has 4 divisors (see below), whose sum is σ = 16029521528. Its totient is φ = 8014760760.
The previous prime is 12022141129. The next prime is 12022141199. The reversal of 12022141143 is 34114122021.
12022141143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12022141143 - 213 = 12022132951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12022141543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003690188 + ... + 2003690193.
It is an arithmetic number, because the mean of its divisors is an integer number (4007380382).
Almost surely, 212022141143 is an apocalyptic number.
12022141143 is a deficient number, since it is larger than the sum of its proper divisors (4007380385).
12022141143 is an equidigital number, since it uses as much as digits as its factorization.
12022141143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4007380384.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 12022141143 its reverse (34114122021), we get a palindrome (46136263164).
The spelling of 12022141143 in words is "twelve billion, twenty-two million, one hundred forty-one thousand, one hundred forty-three".
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