Base | Representation |
---|---|
bin | 1010111011110010010001… |
… | …0001111000101111011101 |
3 | 1120120022110022221021112112 |
4 | 2232330210101320233131 |
5 | 3033433002331131031 |
6 | 41322533235243405 |
7 | 2350401605005646 |
oct | 256744421705735 |
9 | 46508408837475 |
10 | 12022222130141 |
11 | 3915660a79113 |
12 | 1421ba1a49565 |
13 | 6928c9576a12 |
14 | 2d7c430626cd |
15 | 15cad3cca62b |
hex | aef24478bdd |
12022222130141 has 2 divisors, whose sum is σ = 12022222130142. Its totient is φ = 12022222130140.
The previous prime is 12022222130117. The next prime is 12022222130147. The reversal of 12022222130141 is 14103122222021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9737426635225 + 2284795494916 = 3120485^2 + 1511554^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12022222130141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12022222130147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011111065070 + 6011111065071.
It is an arithmetic number, because the mean of its divisors is an integer number (6011111065071).
Almost surely, 212022222130141 is an apocalyptic number.
It is an amenable number.
12022222130141 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022222130141 is an equidigital number, since it uses as much as digits as its factorization.
12022222130141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 12022222130141 its reverse (14103122222021), we get a palindrome (26125344352162).
The spelling of 12022222130141 in words is "twelve trillion, twenty-two billion, two hundred twenty-two million, one hundred thirty thousand, one hundred forty-one".
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