12022312013 has 2 divisors, whose sum is σ = 12022312014. Its totient is φ = 12022312012.

The previous prime is 12022311989. The next prime is 12022312021. The reversal of 12022312013 is 31021322021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9841235209 + 2181076804 = 99203^2 + 46702^2 .

It is a cyclic number.

It is not a de Polignac number, because 12022312013 - 2¹⁶ = 12022246477 is a prime.

It is a super-2 number, since 2×12022312013² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12022311982 and 12022312000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12022312513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011156006 + 6011156007.

It is an arithmetic number, because the mean of its divisors is an integer number (6011156007).

Almost surely, 2^12022312013 is an apocalyptic number.

It is an amenable number.

12022312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022312013 is an equidigital number, since it uses as much as digits as its factorization.

12022312013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12022312013 its reverse (31021322021), we get a palindrome (43043634034).

The spelling of 12022312013 in words is "twelve billion, twenty-two million, three hundred twelve thousand, thirteen".