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12022333004335 = 52404466600867
BaseRepresentation
bin1010111011110010101011…
…1000110101101000101111
31120120022202001120021100011
42232330222320311220233
53033433214222114320
641322552235514051
72350404422301223
oct256745270655057
946508661507304
1012022333004335
113915708617585
121422012bb8927
13692916526c54
142d7c53a84783
1515cadd8cc05a
hexaef2ae35a2f

12022333004335 has 4 divisors (see below), whose sum is σ = 14426799605208. Its totient is φ = 9617866403464.

The previous prime is 12022333004317. The next prime is 12022333004351. The reversal of 12022333004335 is 53340033322021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12022333004335 - 225 = 12022299449903 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12022333004297 and 12022333004306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1202233300429 + ... + 1202233300438.

It is an arithmetic number, because the mean of its divisors is an integer number (3606699901302).

Almost surely, 212022333004335 is an apocalyptic number.

12022333004335 is a deficient number, since it is larger than the sum of its proper divisors (2404466600873).

12022333004335 is an equidigital number, since it uses as much as digits as its factorization.

12022333004335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2404466600872.

The product of its (nonzero) digits is 38880, while the sum is 31.

Adding to 12022333004335 its reverse (53340033322021), we get a palindrome (65362366326356).

The spelling of 12022333004335 in words is "twelve trillion, twenty-two billion, three hundred thirty-three million, four thousand, three hundred thirty-five".

Divisors: 1 5 2404466600867 12022333004335