Base | Representation |
---|---|
bin | 1010111011110010101011… |
… | …1000110101101000101111 |
3 | 1120120022202001120021100011 |
4 | 2232330222320311220233 |
5 | 3033433214222114320 |
6 | 41322552235514051 |
7 | 2350404422301223 |
oct | 256745270655057 |
9 | 46508661507304 |
10 | 12022333004335 |
11 | 3915708617585 |
12 | 1422012bb8927 |
13 | 692916526c54 |
14 | 2d7c53a84783 |
15 | 15cadd8cc05a |
hex | aef2ae35a2f |
12022333004335 has 4 divisors (see below), whose sum is σ = 14426799605208. Its totient is φ = 9617866403464.
The previous prime is 12022333004317. The next prime is 12022333004351. The reversal of 12022333004335 is 53340033322021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12022333004335 - 225 = 12022299449903 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12022333004297 and 12022333004306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1202233300429 + ... + 1202233300438.
It is an arithmetic number, because the mean of its divisors is an integer number (3606699901302).
Almost surely, 212022333004335 is an apocalyptic number.
12022333004335 is a deficient number, since it is larger than the sum of its proper divisors (2404466600873).
12022333004335 is an equidigital number, since it uses as much as digits as its factorization.
12022333004335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2404466600872.
The product of its (nonzero) digits is 38880, while the sum is 31.
Adding to 12022333004335 its reverse (53340033322021), we get a palindrome (65362366326356).
The spelling of 12022333004335 in words is "twelve trillion, twenty-two billion, three hundred thirty-three million, four thousand, three hundred thirty-five".
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