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12022424133 = 34007474711
BaseRepresentation
bin10110011001001011…
…11010001001000101
31011000212022102110220
423030211322021011
5144110220033013
65304550134553
7603632630136
oct131445721105
934025272426
1012022424133
11510a388215
1223b6351459
1311979b6445
148209b7c8d
154a56eeb23
hex2cc97a245

12022424133 has 4 divisors (see below), whose sum is σ = 16029898848. Its totient is φ = 8014949420.

The previous prime is 12022424119. The next prime is 12022424143. The reversal of 12022424133 is 33142422021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12022424133 - 25 = 12022424101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12022424143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003737353 + ... + 2003737358.

It is an arithmetic number, because the mean of its divisors is an integer number (4007474712).

Almost surely, 212022424133 is an apocalyptic number.

It is an amenable number.

12022424133 is a deficient number, since it is larger than the sum of its proper divisors (4007474715).

12022424133 is an equidigital number, since it uses as much as digits as its factorization.

12022424133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4007474714.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 12022424133 its reverse (33142422021), we get a palindrome (45164846154).

The spelling of 12022424133 in words is "twelve billion, twenty-two million, four hundred twenty-four thousand, one hundred thirty-three".

Divisors: 1 3 4007474711 12022424133