Search a number
-
+
12023132117 is a prime number
BaseRepresentation
bin10110011001010001…
…00110111111010101
31011000220122101122112
423030220212333111
5144110410211432
65305013240405
7603641636213
oct131450467725
934026571575
1012023132117
11510a821127
1223b6633105
131197ba3779
14820b1dcb3
154a57de7b2
hex2cca26fd5

12023132117 has 2 divisors, whose sum is σ = 12023132118. Its totient is φ = 12023132116.

The previous prime is 12023132083. The next prime is 12023132123. The reversal of 12023132117 is 71123132021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10169915716 + 1853216401 = 100846^2 + 43049^2 .

It is an emirp because it is prime and its reverse (71123132021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12023132117 - 212 = 12023128021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12023132092 and 12023132101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12023182117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011566058 + 6011566059.

It is an arithmetic number, because the mean of its divisors is an integer number (6011566059).

Almost surely, 212023132117 is an apocalyptic number.

It is an amenable number.

12023132117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12023132117 is an equidigital number, since it uses as much as digits as its factorization.

12023132117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 12023132117 its reverse (71123132021), we get a palindrome (83146264138).

The spelling of 12023132117 in words is "twelve billion, twenty-three million, one hundred thirty-two thousand, one hundred seventeen".