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120234431957 is a prime number
BaseRepresentation
bin110111111111010000…
…1111101010111010101
3102111100100021222200112
41233332201331113111
53432220003310312
6131122425052405
711454343544333
oct1577641752725
9374310258615
10120234431957
1146a9a225342
121b376327105
13b4519389c3
145b6852cb53
1531da861d22
hex1bfe87d5d5

120234431957 has 2 divisors, whose sum is σ = 120234431958. Its totient is φ = 120234431956.

The previous prime is 120234431903. The next prime is 120234431959. The reversal of 120234431957 is 759134432021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78108511441 + 42125920516 = 279479^2 + 205246^2 .

It is a cyclic number.

It is not a de Polignac number, because 120234431957 - 210 = 120234430933 is a prime.

Together with 120234431959, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120234431959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60117215978 + 60117215979.

It is an arithmetic number, because the mean of its divisors is an integer number (60117215979).

Almost surely, 2120234431957 is an apocalyptic number.

It is an amenable number.

120234431957 is a deficient number, since it is larger than the sum of its proper divisors (1).

120234431957 is an equidigital number, since it uses as much as digits as its factorization.

120234431957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 41.

Adding to 120234431957 its reverse (759134432021), we get a palindrome (879368863978).

The spelling of 120234431957 in words is "one hundred twenty billion, two hundred thirty-four million, four hundred thirty-one thousand, nine hundred fifty-seven".