Base | Representation |
---|---|
bin | 1010111011111001101000… |
… | …1100001011000111000011 |
3 | 1120120111120012021221210121 |
4 | 2232332122030023013003 |
5 | 3034001030242002003 |
6 | 41323501423241111 |
7 | 2350501615362211 |
oct | 256763214130703 |
9 | 46514505257717 |
10 | 12024200344003 |
11 | 3916486695501 |
12 | 1422454449197 |
13 | 692b53363973 |
14 | 2d7d8da89cb1 |
15 | 15cb9c7d7cbd |
hex | aef9a30b1c3 |
12024200344003 has 4 divisors (see below), whose sum is σ = 12024361581480. Its totient is φ = 12024039106528.
The previous prime is 12024200343997. The next prime is 12024200344019. The reversal of 12024200344003 is 30044300242021.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12024200344003 - 25 = 12024200343971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12024200314003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80506825 + ... + 80656042.
It is an arithmetic number, because the mean of its divisors is an integer number (3006090395370).
Almost surely, 212024200344003 is an apocalyptic number.
12024200344003 is a deficient number, since it is larger than the sum of its proper divisors (161237477).
12024200344003 is an equidigital number, since it uses as much as digits as its factorization.
12024200344003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161237476.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 12024200344003 its reverse (30044300242021), we get a palindrome (42068500586024).
The spelling of 12024200344003 in words is "twelve trillion, twenty-four billion, two hundred million, three hundred forty-four thousand, three".
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