12024414131 has 2 divisors, whose sum is σ = 12024414132. Its totient is φ = 12024414130.

The previous prime is 12024414107. The next prime is 12024414133. The reversal of 12024414131 is 13141442021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12024414131 - 2²⁶ = 11957305267 is a prime.

It is a super-2 number, since 2×12024414131² (a number of 21 digits) contains 22 as substring.

Together with 12024414133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12024414097 and 12024414106.

It is not a weakly prime, because it can be changed into another prime (12024414133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6012207065 + 6012207066.

It is an arithmetic number, because the mean of its divisors is an integer number (6012207066).

Almost surely, 2^12024414131 is an apocalyptic number.

12024414131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12024414131 is an equidigital number, since it uses as much as digits as its factorization.

12024414131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 12024414131 its reverse (13141442021), we get a palindrome (25165856152).

The spelling of 12024414131 in words is "twelve billion, twenty-four million, four hundred fourteen thousand, one hundred thirty-one".