Base | Representation |
---|---|
bin | 10110011010000101… |
… | …01001010011011101 |
3 | 1011001101111011002121 |
4 | 23031002221103131 |
5 | 144114132113331 |
6 | 5305415422541 |
7 | 604053643633 |
oct | 131502512335 |
9 | 34041434077 |
10 | 12029957341 |
11 | 5113663006 |
12 | 23b8984a51 |
13 | 119942326c |
14 | 8219b9353 |
15 | 4a61dbc11 |
hex | 2cd0a94dd |
12029957341 has 2 divisors, whose sum is σ = 12029957342. Its totient is φ = 12029957340.
The previous prime is 12029957323. The next prime is 12029957347. The reversal of 12029957341 is 14375992021.
12029957341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10408284441 + 1621672900 = 102021^2 + 40270^2 .
It is a cyclic number.
It is not a de Polignac number, because 12029957341 - 231 = 9882473693 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12029957347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6014978670 + 6014978671.
It is an arithmetic number, because the mean of its divisors is an integer number (6014978671).
Almost surely, 212029957341 is an apocalyptic number.
It is an amenable number.
12029957341 is a deficient number, since it is larger than the sum of its proper divisors (1).
12029957341 is an equidigital number, since it uses as much as digits as its factorization.
12029957341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 12029957341 in words is "twelve billion, twenty-nine million, nine hundred fifty-seven thousand, three hundred forty-one".
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