Base | Representation |
---|---|
bin | 1010111100010011011000… |
… | …1010000011001001101111 |
3 | 1120121011101212210110112212 |
4 | 2233010312022003021233 |
5 | 3034104204133000421 |
6 | 41331003324121035 |
7 | 2351135112444131 |
oct | 257046612031157 |
9 | 46534355713485 |
10 | 12031112000111 |
11 | 3919403089a96 |
12 | 142386309617b |
13 | 6936b52776c9 |
14 | 2d84479ab051 |
15 | 15ce544a0e5b |
hex | af13628326f |
12031112000111 has 2 divisors, whose sum is σ = 12031112000112. Its totient is φ = 12031112000110.
The previous prime is 12031112000107. The next prime is 12031112000113. The reversal of 12031112000111 is 11100021113021.
12031112000111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12031112000111 - 22 = 12031112000107 is a prime.
Together with 12031112000113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12031112000113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6015556000055 + 6015556000056.
It is an arithmetic number, because the mean of its divisors is an integer number (6015556000056).
Almost surely, 212031112000111 is an apocalyptic number.
12031112000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12031112000111 is an equidigital number, since it uses as much as digits as its factorization.
12031112000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 12031112000111 its reverse (11100021113021), we get a palindrome (23131133113132).
The spelling of 12031112000111 in words is "twelve trillion, thirty-one billion, one hundred twelve million, one hundred eleven", and thus it is an aban number.
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