Base | Representation |
---|---|
bin | 1010111100010100000101… |
… | …0111101001001011001111 |
3 | 1120121011212222202121001201 |
4 | 2233011001113221023033 |
5 | 3034110100312104403 |
6 | 41331034124050331 |
7 | 2351142555412405 |
oct | 257050127511317 |
9 | 46534788677051 |
10 | 12031300113103 |
11 | 391949a293077 |
12 | 14238b60939a7 |
13 | 69371522c27b |
14 | 2d8464977475 |
15 | 15ce65c5d21d |
hex | af1415e92cf |
12031300113103 has 4 divisors (see below), whose sum is σ = 12031329760240. Its totient is φ = 12031270465968.
The previous prime is 12031300113073. The next prime is 12031300113127. The reversal of 12031300113103 is 30131100313021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12031300113103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12031301113103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14206275 + ... + 15029332.
It is an arithmetic number, because the mean of its divisors is an integer number (3007832440060).
Almost surely, 212031300113103 is an apocalyptic number.
12031300113103 is a deficient number, since it is larger than the sum of its proper divisors (29647137).
12031300113103 is an equidigital number, since it uses as much as digits as its factorization.
12031300113103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29647136.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 12031300113103 its reverse (30131100313021), we get a palindrome (42162400426124).
The spelling of 12031300113103 in words is "twelve trillion, thirty-one billion, three hundred million, one hundred thirteen thousand, one hundred three".
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