Base | Representation |
---|---|
bin | 10110011010010101… |
… | …00011110110010011 |
3 | 1011001112101120012021 |
4 | 23031022203312103 |
5 | 144120200012042 |
6 | 5305532112311 |
7 | 604110404632 |
oct | 131512436623 |
9 | 34045346167 |
10 | 12032032147 |
11 | 511484a923 |
12 | 23b9605697 |
13 | 119999b765 |
14 | 821d99519 |
15 | 4a649b867 |
hex | 2cd2a3d93 |
12032032147 has 2 divisors, whose sum is σ = 12032032148. Its totient is φ = 12032032146.
The previous prime is 12032032039. The next prime is 12032032163. The reversal of 12032032147 is 74123023021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12032032147 is a prime.
It is not a weakly prime, because it can be changed into another prime (12032012147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6016016073 + 6016016074.
It is an arithmetic number, because the mean of its divisors is an integer number (6016016074).
Almost surely, 212032032147 is an apocalyptic number.
12032032147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12032032147 is an equidigital number, since it uses as much as digits as its factorization.
12032032147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 12032032147 its reverse (74123023021), we get a palindrome (86155055168).
The spelling of 12032032147 in words is "twelve billion, thirty-two million, thirty-two thousand, one hundred forty-seven".
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