12032140433 has 2 divisors, whose sum is σ = 12032140434. Its totient is φ = 12032140432.

The previous prime is 12032140429. The next prime is 12032140487. The reversal of 12032140433 is 33404123021.

12032140433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6930895504 + 5101244929 = 83252^2 + 71423^2 .

It is a cyclic number.

It is not a de Polignac number, because 12032140433 - 2² = 12032140429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12032140399 and 12032140408.

It is not a weakly prime, because it can be changed into another prime (12032140493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6016070216 + 6016070217.

It is an arithmetic number, because the mean of its divisors is an integer number (6016070217).

Almost surely, 2^12032140433 is an apocalyptic number.

It is an amenable number.

12032140433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12032140433 is an equidigital number, since it uses as much as digits as its factorization.

12032140433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 12032140433 its reverse (33404123021), we get a palindrome (45436263454).

The spelling of 12032140433 in words is "twelve billion, thirty-two million, one hundred forty thousand, four hundred thirty-three".