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120331310113 = 717190187159
BaseRepresentation
bin111000000010001001…
…1100001010000100001
3102111121002120220112101
41300010103201100201
53432414303410423
6131140205330401
711456631155050
oct1600423412041
9374532526471
10120331310113
1147039984333
121b3a2866a01
13b468a28561
145b7734a397
1531e40eb7ad
hex1c044e1421

120331310113 has 4 divisors (see below), whose sum is σ = 137521497280. Its totient is φ = 103141122948.

The previous prime is 120331310111. The next prime is 120331310119. The reversal of 120331310113 is 311013133021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120331310113 - 21 = 120331310111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120331310111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8595093573 + ... + 8595093586.

It is an arithmetic number, because the mean of its divisors is an integer number (34380374320).

Almost surely, 2120331310113 is an apocalyptic number.

It is an amenable number.

120331310113 is a deficient number, since it is larger than the sum of its proper divisors (17190187167).

120331310113 is an equidigital number, since it uses as much as digits as its factorization.

120331310113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17190187166.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 120331310113 its reverse (311013133021), we get a palindrome (431344443134).

The spelling of 120331310113 in words is "one hundred twenty billion, three hundred thirty-one million, three hundred ten thousand, one hundred thirteen".

Divisors: 1 7 17190187159 120331310113