Base | Representation |
---|---|
bin | 10001100000110001101… |
… | …011011101111110001111 |
3 | 11021001020201011122212211 |
4 | 101200301223131332033 |
5 | 124204103111241143 |
6 | 2320502343411251 |
7 | 152641655645302 |
oct | 21406153357617 |
9 | 4231221148784 |
10 | 1203424321423 |
11 | 4244077244a5 |
12 | 175294453b27 |
13 | 89636b77bbc |
14 | 42363226b39 |
15 | 2148564949d |
hex | 11831addf8f |
1203424321423 has 4 divisors (see below), whose sum is σ = 1223821343880. Its totient is φ = 1183027298968.
The previous prime is 1203424321399. The next prime is 1203424321441. The reversal of 1203424321423 is 3241234243021.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1203424321423 - 217 = 1203424190351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1203424321123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10198511140 + ... + 10198511257.
It is an arithmetic number, because the mean of its divisors is an integer number (305955335970).
Almost surely, 21203424321423 is an apocalyptic number.
1203424321423 is a deficient number, since it is larger than the sum of its proper divisors (20397022457).
1203424321423 is an equidigital number, since it uses as much as digits as its factorization.
1203424321423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20397022456.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1203424321423 its reverse (3241234243021), we get a palindrome (4444658564444).
The spelling of 1203424321423 in words is "one trillion, two hundred three billion, four hundred twenty-four million, three hundred twenty-one thousand, four hundred twenty-three".
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