Base | Representation |
---|---|
bin | 1010111100110100111010… |
… | …1010100100100000010111 |
3 | 1120122000122011222101022102 |
4 | 2233031032222210200113 |
5 | 3034231122424104421 |
6 | 41335052425152315 |
7 | 2351604140602106 |
oct | 257151652444027 |
9 | 46560564871272 |
10 | 12040113113111 |
11 | 3922201a70456 |
12 | 142555562b69b |
13 | 6944bb027485 |
14 | 2d8a5d1d203d |
15 | 15d2ce7ec60b |
hex | af34eaa4817 |
12040113113111 has 4 divisors (see below), whose sum is σ = 12040144267800. Its totient is φ = 12040081958424.
The previous prime is 12040113113089. The next prime is 12040113113141. The reversal of 12040113113111 is 11131131104021.
12040113113111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12040113113111 - 214 = 12040113096727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12040113113141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14990276 + ... + 15773033.
It is an arithmetic number, because the mean of its divisors is an integer number (3010036066950).
Almost surely, 212040113113111 is an apocalyptic number.
12040113113111 is a deficient number, since it is larger than the sum of its proper divisors (31154689).
12040113113111 is an equidigital number, since it uses as much as digits as its factorization.
12040113113111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31154688.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 12040113113111 its reverse (11131131104021), we get a palindrome (23171244217132).
The spelling of 12040113113111 in words is "twelve trillion, forty billion, one hundred thirteen million, one hundred thirteen thousand, one hundred eleven".
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