12040251351313 has 4 divisors (see below), whose sum is σ = 12748501430820. Its totient is φ = 11332001271808.

The previous prime is 12040251351299. The next prime is 12040251351389. The reversal of 12040251351313 is 31315315204021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4572339719809 + 7467911631504 = 2138303^2 + 2732748^2 .

It is a cyclic number.

It is not a de Polignac number, because 12040251351313 - 2⁹ = 12040251350801 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12040251351113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 354125039728 + ... + 354125039761.

It is an arithmetic number, because the mean of its divisors is an integer number (3187125357705).

Almost surely, 2^{12040251351313} is an apocalyptic number.

It is an amenable number.

12040251351313 is a deficient number, since it is larger than the sum of its proper divisors (708250079507).

12040251351313 is an equidigital number, since it uses as much as digits as its factorization.

12040251351313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 708250079506.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 12040251351313 its reverse (31315315204021), we get a palindrome (43355566555334).

The spelling of 12040251351313 in words is "twelve trillion, forty billion, two hundred fifty-one million, three hundred fifty-one thousand, three hundred thirteen".