Base | Representation |
---|---|
bin | 111000000100010100… |
… | …1101100010011110101 |
3 | 102111210011210200202021 |
4 | 1300020221230103311 |
5 | 3433041440401123 |
6 | 131151332313141 |
7 | 11461505036434 |
oct | 1601051542365 |
9 | 374704720667 |
10 | 120404231413 |
11 | 47077060174 |
12 | 1b4031727b1 |
13 | b47ab7a95b |
14 | 5b82ccd11b |
15 | 31ea702c5d |
hex | 1c08a6c4f5 |
120404231413 has 2 divisors, whose sum is σ = 120404231414. Its totient is φ = 120404231412.
The previous prime is 120404231393. The next prime is 120404231459. The reversal of 120404231413 is 314132404021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112588433764 + 7815797649 = 335542^2 + 88407^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120404231413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120464231413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60202115706 + 60202115707.
It is an arithmetic number, because the mean of its divisors is an integer number (60202115707).
Almost surely, 2120404231413 is an apocalyptic number.
It is an amenable number.
120404231413 is a deficient number, since it is larger than the sum of its proper divisors (1).
120404231413 is an equidigital number, since it uses as much as digits as its factorization.
120404231413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 120404231413 its reverse (314132404021), we get a palindrome (434536635434).
The spelling of 120404231413 in words is "one hundred twenty billion, four hundred four million, two hundred thirty-one thousand, four hundred thirteen".
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