Base | Representation |
---|---|
bin | 11011011000001111100010… |
… | …000010011001110100001111 |
3 | 120210100101111222021102201112 |
4 | 123120033202002121310033 |
5 | 111240322213302033312 |
6 | 1104033021032002235 |
7 | 34235365233635015 |
oct | 3330174202316417 |
9 | 523311458242645 |
10 | 120413200424207 |
11 | 35404a515236a9 |
12 | 11608a7523037b |
13 | 5225bba8120c2 |
14 | 21a405c4508b5 |
15 | ddc354d90d22 |
hex | 6d83e2099d0f |
120413200424207 has 2 divisors, whose sum is σ = 120413200424208. Its totient is φ = 120413200424206.
The previous prime is 120413200424191. The next prime is 120413200424213. The reversal of 120413200424207 is 702424002314021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120413200424207 - 24 = 120413200424191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120413200424107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60206600212103 + 60206600212104.
It is an arithmetic number, because the mean of its divisors is an integer number (60206600212104).
Almost surely, 2120413200424207 is an apocalyptic number.
120413200424207 is a deficient number, since it is larger than the sum of its proper divisors (1).
120413200424207 is an equidigital number, since it uses as much as digits as its factorization.
120413200424207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 120413200424207 its reverse (702424002314021), we get a palindrome (822837202738228).
The spelling of 120413200424207 in words is "one hundred twenty trillion, four hundred thirteen billion, two hundred million, four hundred twenty-four thousand, two hundred seven".
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