Base | Representation |
---|---|
bin | 10110011011101100… |
… | …00110010100100110 |
3 | 1011002022212102102121 |
4 | 23031312012110212 |
5 | 144131110224132 |
6 | 5311020500154 |
7 | 604306412062 |
oct | 131566062446 |
9 | 34068772377 |
10 | 12043445542 |
11 | 5120235987 |
12 | 24013aa65a |
13 | 119c16674b |
14 | 8236caaa2 |
15 | 4a74a3497 |
hex | 2cdd86526 |
12043445542 has 4 divisors (see below), whose sum is σ = 18065168316. Its totient is φ = 6021722770.
The previous prime is 12043445501. The next prime is 12043445549. The reversal of 12043445542 is 24554434021.
12043445542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 12043445498 and 12043445507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12043445549) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3010861384 + ... + 3010861387.
It is an arithmetic number, because the mean of its divisors is an integer number (4516292079).
Almost surely, 212043445542 is an apocalyptic number.
12043445542 is a deficient number, since it is larger than the sum of its proper divisors (6021722774).
12043445542 is an equidigital number, since it uses as much as digits as its factorization.
12043445542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6021722773.
The product of its (nonzero) digits is 76800, while the sum is 34.
Adding to 12043445542 its reverse (24554434021), we get a palindrome (36597879563).
The spelling of 12043445542 in words is "twelve billion, forty-three million, four hundred forty-five thousand, five hundred forty-two".
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