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12054404413 = 29303411371
BaseRepresentation
bin10110011100111111…
…11001110100111101
31011010002111012011201
423032133321310331
5144141411420123
65312051415501
7604501514122
oct131637716475
934102435151
1012054404413
1151264404a7
122404bb4591
1311a150289c
14824d40749
154a841a5ad
hex2ce7f9d3d

12054404413 has 4 divisors (see below), whose sum is σ = 12054845088. Its totient is φ = 12053963740.

The previous prime is 12054404399. The next prime is 12054404419. The reversal of 12054404413 is 31440445021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12054404413 - 29 = 12054403901 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12054404419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176383 + ... + 234988.

It is an arithmetic number, because the mean of its divisors is an integer number (3013711272).

Almost surely, 212054404413 is an apocalyptic number.

It is an amenable number.

12054404413 is a deficient number, since it is larger than the sum of its proper divisors (440675).

12054404413 is an equidigital number, since it uses as much as digits as its factorization.

12054404413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440674.

The product of its (nonzero) digits is 7680, while the sum is 28.

Adding to 12054404413 its reverse (31440445021), we get a palindrome (43494849434).

The spelling of 12054404413 in words is "twelve billion, fifty-four million, four hundred four thousand, four hundred thirteen".

Divisors: 1 29303 411371 12054404413