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12064063041535 = 52412812608307
BaseRepresentation
bin1010111110001110001000…
…1100010010111111111111
31120201022110021222210201111
42233203202030102333333
53040124200114312120
641354053135222451
72353412504616241
oct257434214227777
946638407883644
1012064063041535
11393138209412a
12142a11a377a27
13696836b4195b
142d9c91d16091
1515dc321ec75a
hexaf8e2312fff

12064063041535 has 4 divisors (see below), whose sum is σ = 14476875649848. Its totient is φ = 9651250433224.

The previous prime is 12064063041509. The next prime is 12064063041539. The reversal of 12064063041535 is 53514036046021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12064063041535 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12064063041539) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1206406304149 + ... + 1206406304158.

It is an arithmetic number, because the mean of its divisors is an integer number (3619218912462).

Almost surely, 212064063041535 is an apocalyptic number.

12064063041535 is a deficient number, since it is larger than the sum of its proper divisors (2412812608313).

12064063041535 is an equidigital number, since it uses as much as digits as its factorization.

12064063041535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2412812608312.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 12064063041535 its reverse (53514036046021), we get a palindrome (65578099087556).

The spelling of 12064063041535 in words is "twelve trillion, sixty-four billion, sixty-three million, forty-one thousand, five hundred thirty-five".

Divisors: 1 5 2412812608307 12064063041535