Base | Representation |
---|---|
bin | 10110011111100111… |
… | …10001000111100011 |
3 | 1011011121212010010120 |
4 | 23033303301013203 |
5 | 144213023420320 |
6 | 5314154531323 |
7 | 605156416500 |
oct | 131763610743 |
9 | 34147763116 |
10 | 12076388835 |
11 | 5137896745 |
12 | 2410436b43 |
13 | 11a5c2c314 |
14 | 827c244a7 |
15 | 4aa30e440 |
hex | 2cfcf11e3 |
12076388835 has 96 divisors (see below), whose sum is σ = 22771487232. Its totient is φ = 5448844800.
The previous prime is 12076388833. The next prime is 12076388837. The reversal of 12076388835 is 53888367021.
It is an interprime number because it is at equal distance from previous prime (12076388833) and next prime (12076388837).
It is not a de Polignac number, because 12076388835 - 21 = 12076388833 is a prime.
It is a super-2 number, since 2×120763888352 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12076388833) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 25859272 + ... + 25859738.
It is an arithmetic number, because the mean of its divisors is an integer number (237202992).
Almost surely, 212076388835 is an apocalyptic number.
12076388835 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12076388835 is a deficient number, since it is larger than the sum of its proper divisors (10695098397).
12076388835 is a wasteful number, since it uses less digits than its factorization.
12076388835 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 873 (or 866 counting only the distinct ones).
The product of its (nonzero) digits is 1935360, while the sum is 51.
The spelling of 12076388835 in words is "twelve billion, seventy-six million, three hundred eighty-eight thousand, eight hundred thirty-five".
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