Base | Representation |
---|---|
bin | 1010111111010111110010… |
… | …0101111111100011010111 |
3 | 1120210012111010021221001112 |
4 | 2233311330211333203113 |
5 | 3040440142313304241 |
6 | 41411123021245235 |
7 | 2355012440433605 |
oct | 257657445774327 |
9 | 46705433257045 |
10 | 12083833338071 |
11 | 39397a7992580 |
12 | 1431b1740381b |
13 | 698667a62281 |
14 | 2dac098c6875 |
15 | 15e4dcbe31eb |
hex | afd7c97f8d7 |
12083833338071 has 16 divisors (see below), whose sum is σ = 13792388037120. Its totient is φ = 10479510354720.
The previous prime is 12083833338041. The next prime is 12083833338079. The reversal of 12083833338071 is 17083333838021.
It is not a de Polignac number, because 12083833338071 - 214 = 12083833321687 is a prime.
It is a super-2 number, since 2×120838333380712 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12083833338079) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63930011 + ... + 64118748.
It is an arithmetic number, because the mean of its divisors is an integer number (862024252320).
Almost surely, 212083833338071 is an apocalyptic number.
12083833338071 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
12083833338071 is a deficient number, since it is larger than the sum of its proper divisors (1708554699049).
12083833338071 is a wasteful number, since it uses less digits than its factorization.
12083833338071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128049166.
The product of its (nonzero) digits is 1741824, while the sum is 50.
It can be divided in two parts, 1208383 and 3338071, that added together give a palindrome (4546454).
The spelling of 12083833338071 in words is "twelve trillion, eighty-three billion, eight hundred thirty-three million, three hundred thirty-eight thousand, seventy-one".
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