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1208889415117 is a prime number
BaseRepresentation
bin10001100101110111011…
…011001001010111001101
311021120100120201012001101
4101211313123021113031
5124301301142240432
62323204531343101
7153224256325126
oct21456733112715
94246316635041
101208889415117
1142676161725a
1217635a751a91
1389cc8189657
1442720d9504d
15216a53214e7
hex119776c95cd

1208889415117 has 2 divisors, whose sum is σ = 1208889415118. Its totient is φ = 1208889415116.

The previous prime is 1208889415109. The next prime is 1208889415141. The reversal of 1208889415117 is 7115149888021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1208550634281 + 338780836 = 1099341^2 + 18406^2 .

It is a cyclic number.

It is not a de Polignac number, because 1208889415117 - 23 = 1208889415109 is a prime.

It is a super-2 number, since 2×12088894151172 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1208889410117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 604444707558 + 604444707559.

It is an arithmetic number, because the mean of its divisors is an integer number (604444707559).

Almost surely, 21208889415117 is an apocalyptic number.

It is an amenable number.

1208889415117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1208889415117 is an equidigital number, since it uses as much as digits as its factorization.

1208889415117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1290240, while the sum is 55.

The spelling of 1208889415117 in words is "one trillion, two hundred eight billion, eight hundred eighty-nine million, four hundred fifteen thousand, one hundred seventeen".