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121000013303 = 139307693331
BaseRepresentation
bin111000010110000101…
…0011010110111110111
3102120022200212112212012
41300230022122313313
53440302000411203
6131330414114435
711512331100041
oct1605412326767
9376280775765
10121000013303
11473523979a4
121b54a7aba1b
13b54442a610
145bdc098a91
153232b8abd8
hex1c2c29adf7

121000013303 has 4 divisors (see below), whose sum is σ = 130307706648. Its totient is φ = 111692319960.

The previous prime is 121000013291. The next prime is 121000013363. The reversal of 121000013303 is 303310000121.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-121000013303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121000013363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4653846653 + ... + 4653846678.

It is an arithmetic number, because the mean of its divisors is an integer number (32576926662).

Almost surely, 2121000013303 is an apocalyptic number.

121000013303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

121000013303 is a deficient number, since it is larger than the sum of its proper divisors (9307693345).

121000013303 is an equidigital number, since it uses as much as digits as its factorization.

121000013303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9307693344.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 121000013303 its reverse (303310000121), we get a palindrome (424310013424).

The spelling of 121000013303 in words is "one hundred twenty-one billion, thirteen thousand, three hundred three".

Divisors: 1 13 9307693331 121000013303