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121000013333 = 1031174757411
BaseRepresentation
bin111000010110000101…
…0011010111000010101
3102120022200212112220022
41300230022122320111
53440302000411313
6131330414114525
711512331100113
oct1605412327025
9376280775808
10121000013333
1147352397a21
121b54a7aba45
13b54442a634
145bdc098ab3
153232b8ac08
hex1c2c29ae15

121000013333 has 4 divisors (see below), whose sum is σ = 122174770848. Its totient is φ = 119825255820.

The previous prime is 121000013291. The next prime is 121000013363. The reversal of 121000013333 is 333310000121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121000013333 - 28 = 121000013077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121000013363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 587378603 + ... + 587378808.

It is an arithmetic number, because the mean of its divisors is an integer number (30543692712).

Almost surely, 2121000013333 is an apocalyptic number.

It is an amenable number.

121000013333 is a deficient number, since it is larger than the sum of its proper divisors (1174757515).

121000013333 is a wasteful number, since it uses less digits than its factorization.

121000013333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1174757514.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 121000013333 its reverse (333310000121), we get a palindrome (454310013454).

The spelling of 121000013333 in words is "one hundred twenty-one billion, thirteen thousand, three hundred thirty-three".

Divisors: 1 103 1174757411 121000013333