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121000112113 = 313903229423
BaseRepresentation
bin111000010110000101…
…0110010111111110001
3102120022201001120101211
41300230022302333301
53440302012041423
6131330420200121
711512331661106
oct1605412627761
9376281046354
10121000112113
1147352455161
121b54a839041
13b54446359a
145bdc0c2aad
153232baa10d
hex1c2c2b2ff1

121000112113 has 4 divisors (see below), whose sum is σ = 124903341568. Its totient is φ = 117096882660.

The previous prime is 121000112087. The next prime is 121000112153. The reversal of 121000112113 is 311211000121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121000112113 - 221 = 120998014961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121000112093 and 121000112102.

It is not an unprimeable number, because it can be changed into a prime (121000112153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1951614681 + ... + 1951614742.

It is an arithmetic number, because the mean of its divisors is an integer number (31225835392).

Almost surely, 2121000112113 is an apocalyptic number.

It is an amenable number.

121000112113 is a deficient number, since it is larger than the sum of its proper divisors (3903229455).

121000112113 is an equidigital number, since it uses as much as digits as its factorization.

121000112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3903229454.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 121000112113 its reverse (311211000121), we get a palindrome (432211112234).

The spelling of 121000112113 in words is "one hundred twenty-one billion, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 31 3903229423 121000112113