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121001101220222 = 260500550610111
BaseRepresentation
bin11011100000110011000011…
…101001111101100101111110
3120212102120222210100020120122
4123200303003221331211332
5111324440223403021342
61105203045530214542
734326020042150606
oct3340630351754576
9525376883306518
10121001101220222
1135611308168163
12116a29a7b84452
13526947c8b26c2
1421c46ad851c06
15dec7b28e44d2
hex6e0cc3a7d97e

121001101220222 has 4 divisors (see below), whose sum is σ = 181501651830336. Its totient is φ = 60500550610110.

The previous prime is 121001101220221. The next prime is 121001101220249. The reversal of 121001101220222 is 222022101100121.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 121001101220222.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121001101220221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30250275305054 + ... + 30250275305057.

It is an arithmetic number, because the mean of its divisors is an integer number (45375412957584).

Almost surely, 2121001101220222 is an apocalyptic number.

121001101220222 is a deficient number, since it is larger than the sum of its proper divisors (60500550610114).

121001101220222 is an equidigital number, since it uses as much as digits as its factorization.

121001101220222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60500550610113.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 121001101220222 its reverse (222022101100121), we get a palindrome (343023202320343).

The spelling of 121001101220222 in words is "one hundred twenty-one trillion, one billion, one hundred one million, two hundred twenty thousand, two hundred twenty-two".

Divisors: 1 2 60500550610111 121001101220222