Base | Representation |
---|---|
bin | 11011100000110011000100… |
… | …010011100000011110011001 |
3 | 120212102121000112211112220211 |
4 | 123200303010103200132121 |
5 | 111324440234200023001 |
6 | 1105203050555451121 |
7 | 34326020233550263 |
oct | 3340630423403631 |
9 | 525377015745824 |
10 | 121001112111001 |
11 | 35611313326601 |
12 | 116a29ab756aa1 |
13 | 5269481c26855 |
14 | 21c46b1088b33 |
15 | dec7b3846351 |
hex | 6e0cc44e0799 |
121001112111001 has 2 divisors, whose sum is σ = 121001112111002. Its totient is φ = 121001112111000.
The previous prime is 121001112110939. The next prime is 121001112111073. The reversal of 121001112111001 is 100111211100121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63374718758976 + 57626393352025 = 7960824^2 + 7591205^2 .
It is a cyclic number.
It is not a de Polignac number, because 121001112111001 - 219 = 121001111586713 is a prime.
It is not a weakly prime, because it can be changed into another prime (121001112118001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500556055500 + 60500556055501.
It is an arithmetic number, because the mean of its divisors is an integer number (60500556055501).
Almost surely, 2121001112111001 is an apocalyptic number.
It is an amenable number.
121001112111001 is a deficient number, since it is larger than the sum of its proper divisors (1).
121001112111001 is an equidigital number, since it uses as much as digits as its factorization.
121001112111001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 121001112111001 its reverse (100111211100121), we get a palindrome (221112323211122).
The spelling of 121001112111001 in words is "one hundred twenty-one trillion, one billion, one hundred twelve million, one hundred eleven thousand, one".
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