Base | Representation |
---|---|
bin | 10001100110111010010… |
… | …010110111111100111011 |
3 | 11021200020202202212101122 |
4 | 101212322102313330323 |
5 | 124311100344220443 |
6 | 2323512125535455 |
7 | 153264131343164 |
oct | 21467222677473 |
9 | 4250222685348 |
10 | 1210011320123 |
11 | 427187933081 |
12 | 17661241458b |
13 | 8a146739878 |
14 | 427c9d9676b |
15 | 2171da82968 |
hex | 119ba4b7f3b |
1210011320123 has 2 divisors, whose sum is σ = 1210011320124. Its totient is φ = 1210011320122.
The previous prime is 1210011320117. The next prime is 1210011320153. The reversal of 1210011320123 is 3210231100121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210011320123 - 26 = 1210011320059 is a prime.
It is not a weakly prime, because it can be changed into another prime (1210011320153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605005660061 + 605005660062.
It is an arithmetic number, because the mean of its divisors is an integer number (605005660062).
Almost surely, 21210011320123 is an apocalyptic number.
1210011320123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210011320123 is an equidigital number, since it uses as much as digits as its factorization.
1210011320123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1210011320123 its reverse (3210231100121), we get a palindrome (4420242420244).
The spelling of 1210011320123 in words is "one trillion, two hundred ten billion, eleven million, three hundred twenty thousand, one hundred twenty-three".
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