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121002000113 is a prime number
BaseRepresentation
bin111000010110001000…
…1111111111011110001
3102120022211121111020202
41300230101333323301
53440303003000423
6131330524444545
711512354013351
oct1605421777361
9376284544222
10121002000113
1147353524695
121b54b3a9755
13b544974a47
145bdc454b61
153232e2e728
hex1c2c47fef1

121002000113 has 2 divisors, whose sum is σ = 121002000114. Its totient is φ = 121002000112.

The previous prime is 121002000047. The next prime is 121002000143. The reversal of 121002000113 is 311000200121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70038034609 + 50963965504 = 264647^2 + 225752^2 .

It is a cyclic number.

It is not a de Polignac number, because 121002000113 - 28 = 121001999857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121002000094 and 121002000103.

It is not a weakly prime, because it can be changed into another prime (121002000143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501000056 + 60501000057.

It is an arithmetic number, because the mean of its divisors is an integer number (60501000057).

Almost surely, 2121002000113 is an apocalyptic number.

It is an amenable number.

121002000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121002000113 is an equidigital number, since it uses as much as digits as its factorization.

121002000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 121002000113 its reverse (311000200121), we get a palindrome (432002200234).

The spelling of 121002000113 in words is "one hundred twenty-one billion, two million, one hundred thirteen", and thus it is an aban number.