Base | Representation |
---|---|
bin | 111000010110001000… |
… | …1111111111010101111 |
3 | 102120022211121111011022 |
4 | 1300230101333322233 |
5 | 3440303003000142 |
6 | 131330524444355 |
7 | 11512354013225 |
oct | 1605421777257 |
9 | 376284544138 |
10 | 121002000047 |
11 | 47353524635 |
12 | 1b54b3a96bb |
13 | b5449749c6 |
14 | 5bdc454b15 |
15 | 3232e2e6d2 |
hex | 1c2c47feaf |
121002000047 has 2 divisors, whose sum is σ = 121002000048. Its totient is φ = 121002000046.
The previous prime is 121002000037. The next prime is 121002000113. The reversal of 121002000047 is 740000200121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121002000047 - 210 = 121001999023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121001999989 and 121002000034.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121002000037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501000023 + 60501000024.
It is an arithmetic number, because the mean of its divisors is an integer number (60501000024).
Almost surely, 2121002000047 is an apocalyptic number.
121002000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
121002000047 is an equidigital number, since it uses as much as digits as its factorization.
121002000047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 121002000047 its reverse (740000200121), we get a palindrome (861002200168).
The spelling of 121002000047 in words is "one hundred twenty-one billion, two million, forty-seven", and thus it is an aban number.
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