12100211200303 has 4 divisors (see below), whose sum is σ = 12100222031128. Its totient is φ = 12100200369480.

The previous prime is 12100211200279. The next prime is 12100211200309. The reversal of 12100211200303 is 30300211200121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12100211200303 is a prime.

It is a super-4 number, since 4×12100211200303⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12100211200309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3518013 + ... + 6047878.

It is an arithmetic number, because the mean of its divisors is an integer number (3025055507782).

Almost surely, 2^{12100211200303} is an apocalyptic number.

12100211200303 is a deficient number, since it is larger than the sum of its proper divisors (10830825).

12100211200303 is an equidigital number, since it uses as much as digits as its factorization.

12100211200303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10830824.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12100211200303 its reverse (30300211200121), we get a palindrome (42400422400424).

The spelling of 12100211200303 in words is "twelve trillion, one hundred billion, two hundred eleven million, two hundred thousand, three hundred three".