Base | Representation |
---|---|
bin | 111000010110001001… |
… | …0110011111101111111 |
3 | 102120022212000022121121 |
4 | 1300230102303331333 |
5 | 3440303031310442 |
6 | 131330533211411 |
7 | 11512355561626 |
oct | 1605422637577 |
9 | 376285008547 |
10 | 121002213247 |
11 | 4735365a833 |
12 | 1b54b490b67 |
13 | b544a1aa66 |
14 | 5bdc4ac6bd |
15 | 3232e72967 |
hex | 1c2c4b3f7f |
121002213247 has 2 divisors, whose sum is σ = 121002213248. Its totient is φ = 121002213246.
The previous prime is 121002213197. The next prime is 121002213263. The reversal of 121002213247 is 742312200121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121002213247 - 223 = 120993824639 is a prime.
It is a super-2 number, since 2×1210022132472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121002213047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501106623 + 60501106624.
It is an arithmetic number, because the mean of its divisors is an integer number (60501106624).
Almost surely, 2121002213247 is an apocalyptic number.
121002213247 is a deficient number, since it is larger than the sum of its proper divisors (1).
121002213247 is an equidigital number, since it uses as much as digits as its factorization.
121002213247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 121002213247 its reverse (742312200121), we get a palindrome (863314413368).
The spelling of 121002213247 in words is "one hundred twenty-one billion, two million, two hundred thirteen thousand, two hundred forty-seven".
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