121004113 has 4 divisors (see below), whose sum is σ = 128122020. Its totient is φ = 113886208.

The previous prime is 121004089. The next prime is 121004119. The reversal of 121004113 is 311400121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311400121 = 67 ⋅4647763.

It can be written as a sum of positive squares in 2 ways, for example, as 55830784 + 65173329 = 7472^2 + 8073^2 .

It is a cyclic number.

It is not a de Polignac number, because 121004113 - 2⁹ = 121003601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121004093 and 121004102.

It is not an unprimeable number, because it can be changed into a prime (121004119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3558928 + ... + 3558961.

It is an arithmetic number, because the mean of its divisors is an integer number (32030505).

Almost surely, 2^121004113 is an apocalyptic number.

It is an amenable number.

121004113 is a deficient number, since it is larger than the sum of its proper divisors (7117907).

121004113 is an equidigital number, since it uses as much as digits as its factorization.

121004113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7117906.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 121004113 is about 11000.1869529568. The cubic root of 121004113 is about 494.6143484646.

Adding to 121004113 its reverse (311400121), we get a palindrome (432404234).

The spelling of 121004113 in words is "one hundred twenty-one million, four thousand, one hundred thirteen".