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121005141 = 340335047
BaseRepresentation
bin1110011011001…
…10010001010101
322102200200211220
413031212101111
5221434131031
620001320553
72666345445
oct715462125
9272620756
10121005141
1162338a54
1234636159
131c0b959a
14120dc125
15a953596
hex7366455

121005141 has 4 divisors (see below), whose sum is σ = 161340192. Its totient is φ = 80670092.

The previous prime is 121005127. The next prime is 121005161. The reversal of 121005141 is 141500121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121005141 - 27 = 121005013 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121005141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121005161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20167521 + ... + 20167526.

It is an arithmetic number, because the mean of its divisors is an integer number (40335048).

Almost surely, 2121005141 is an apocalyptic number.

It is an amenable number.

121005141 is a deficient number, since it is larger than the sum of its proper divisors (40335051).

121005141 is an equidigital number, since it uses as much as digits as its factorization.

121005141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40335050.

The product of its (nonzero) digits is 40, while the sum is 15.

The square root of 121005141 is about 11000.2336793361. The cubic root of 121005141 is about 494.6157491390.

Adding to 121005141 its reverse (141500121), we get a palindrome (262505262).

The spelling of 121005141 in words is "one hundred twenty-one million, five thousand, one hundred forty-one".

Divisors: 1 3 40335047 121005141