12101011020223 has 2 divisors, whose sum is σ = 12101011020224. Its totient is φ = 12101011020222.

The previous prime is 12101011020191. The next prime is 12101011020239. The reversal of 12101011020223 is 32202011010121.

It is an a-pointer prime, because the next prime (12101011020239) can be obtained adding 12101011020223 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12101011020223 - 2⁵ = 12101011020191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12101011020197 and 12101011020206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12101017020223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050505510111 + 6050505510112.

It is an arithmetic number, because the mean of its divisors is an integer number (6050505510112).

Almost surely, 2^{12101011020223} is an apocalyptic number.

12101011020223 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101011020223 is an equidigital number, since it uses as much as digits as its factorization.

12101011020223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12101011020223 its reverse (32202011010121), we get a palindrome (44303022030344).

The spelling of 12101011020223 in words is "twelve trillion, one hundred one billion, eleven million, twenty thousand, two hundred twenty-three".