Base | Representation |
---|---|
bin | 10001100110111111101… |
… | …100110011000101011011 |
3 | 11021200111002101222120002 |
4 | 101212333230303011123 |
5 | 124311242103031021 |
6 | 2323525125323215 |
7 | 153266312205650 |
oct | 21467754630533 |
9 | 4250432358502 |
10 | 1210102002011 |
11 | 42722403a791 |
12 | 17663886650b |
13 | 8a15c469ca6 |
14 | 427d803dc27 |
15 | 217269e650b |
hex | 119bfb3315b |
1210102002011 has 4 divisors (see below), whose sum is σ = 1382973716592. Its totient is φ = 1037230287432.
The previous prime is 1210102001939. The next prime is 1210102002013. The reversal of 1210102002011 is 1102002010121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1210102002011 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1210102001983 and 1210102002001.
It is not an unprimeable number, because it can be changed into a prime (1210102002013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86435857280 + ... + 86435857293.
It is an arithmetic number, because the mean of its divisors is an integer number (345743429148).
Almost surely, 21210102002011 is an apocalyptic number.
1210102002011 is a deficient number, since it is larger than the sum of its proper divisors (172871714581).
1210102002011 is an equidigital number, since it uses as much as digits as its factorization.
1210102002011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172871714580.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 1210102002011 its reverse (1102002010121), we get a palindrome (2312104012132).
The spelling of 1210102002011 in words is "one trillion, two hundred ten billion, one hundred two million, two thousand, eleven".
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