12101113211232 has 384 divisors, whose sum is σ = 36239954688000. Its totient is φ = 3512062181376.

The previous prime is 12101113211149. The next prime is 12101113211311. The reversal of 12101113211232 is 23211231110121.

It is a junction number, because it is equal to n+sod(n) for n = 12101113211199 and 12101113211208.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 654352578 + ... + 654371070.

It is an arithmetic number, because the mean of its divisors is an integer number (94374882000).

Almost surely, 2^{12101113211232} is an apocalyptic number.

12101113211232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12101113211232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18119977344000).

12101113211232 is an abundant number, since it is smaller than the sum of its proper divisors (24138841476768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12101113211232 is a wasteful number, since it uses less digits than its factorization.

12101113211232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19038 (or 19030 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 12101113211232 its reverse (23211231110121), we get a palindrome (35312344321353).

The spelling of 12101113211232 in words is "twelve trillion, one hundred one billion, one hundred thirteen million, two hundred eleven thousand, two hundred thirty-two".