12101122099999 has 4 divisors (see below), whose sum is σ = 12220935190200. Its totient is φ = 11981309009800.

The previous prime is 12101122099987. The next prime is 12101122100009. The reversal of 12101122099999 is 99999022110121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12101122099999 - 2¹¹ = 12101122097951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12101122019999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59906544949 + ... + 59906545150.

It is an arithmetic number, because the mean of its divisors is an integer number (3055233797550).

Almost surely, 2^{12101122099999} is an apocalyptic number.

12101122099999 is a deficient number, since it is larger than the sum of its proper divisors (119813090201).

12101122099999 is a wasteful number, since it uses less digits than its factorization.

12101122099999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119813090200.

The product of its (nonzero) digits is 472392, while the sum is 55.

The spelling of 12101122099999 in words is "twelve trillion, one hundred one billion, one hundred twenty-two million, ninety-nine thousand, nine hundred ninety-nine".