Base | Representation |
---|---|
bin | 111000010110011010… |
… | …1111111001101100111 |
3 | 102120100111100210120200 |
4 | 1300230311333031213 |
5 | 3440312411344333 |
6 | 131331503001543 |
7 | 11512530135402 |
oct | 1605465771547 |
9 | 376314323520 |
10 | 121011434343 |
11 | 47358888778 |
12 | 1b5525992b3 |
13 | b5468c8c27 |
14 | 5bdd7ccd39 |
15 | 3233b94c13 |
hex | 1c2cd7f367 |
121011434343 has 12 divisors (see below), whose sum is σ = 178513322208. Its totient is φ = 78957815040.
The previous prime is 121011434333. The next prime is 121011434371. The reversal of 121011434343 is 343434110121.
121011434343 is a `hidden beast` number, since 1 + 210 + 1 + 14 + 3 + 434 + 3 = 666.
It is not a de Polignac number, because 121011434343 - 25 = 121011434311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121011434333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 143039098 + ... + 143039943.
It is an arithmetic number, because the mean of its divisors is an integer number (14876110184).
Almost surely, 2121011434343 is an apocalyptic number.
121011434343 is a deficient number, since it is larger than the sum of its proper divisors (57501887865).
121011434343 is a wasteful number, since it uses less digits than its factorization.
121011434343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 286079094 (or 286079091 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 121011434343 its reverse (343434110121), we get a palindrome (464445544464).
The spelling of 121011434343 in words is "one hundred twenty-one billion, eleven million, four hundred thirty-four thousand, three hundred forty-three".
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