Base | Representation |
---|---|
bin | 1011000000011000100011… |
… | …1111011111111100001110 |
3 | 1120211212100220122212002121 |
4 | 2300012020333133330032 |
5 | 3041231300113020420 |
6 | 41423120240043154 |
7 | 2356166354126341 |
oct | 260061077377416 |
9 | 46755326585077 |
10 | 12101221220110 |
11 | 394610a99a720 |
12 | 143536a6034ba |
13 | 69a1a9213379 |
14 | 2db9b8cd4458 |
15 | 15eba94882aa |
hex | b0188fdff0e |
12101221220110 has 16 divisors (see below), whose sum is σ = 23762398032432. Its totient is φ = 4400444080000.
The previous prime is 12101221219961. The next prime is 12101221220111. The reversal of 12101221220110 is 1102212210121.
It is a super-3 number, since 3×121012212201103 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12101221220111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55005550891 + ... + 55005551110.
It is an arithmetic number, because the mean of its divisors is an integer number (1485149877027).
Almost surely, 212101221220110 is an apocalyptic number.
12101221220110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12101221220110 is a deficient number, since it is larger than the sum of its proper divisors (11661176812322).
12101221220110 is a wasteful number, since it uses less digits than its factorization.
12101221220110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110011102019.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 12101221220110 its reverse (1102212210121), we get a palindrome (13203433430231).
The spelling of 12101221220110 in words is "twelve trillion, one hundred one billion, two hundred twenty-one million, two hundred twenty thousand, one hundred ten".
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